## Random thoughts...

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### Re: Random thoughts...

Deathclaw_Puncher wrote:How many entries on /r/ThatHappened actually happened and were only submitted because of some sort of skepticism that anything positive in life never happens?

All of them, according to my friend who works in the CIA.
That friend?
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cmsellers
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### Re: Random thoughts...

So, what foods and services will the alt-right boycott this year because they marketed to more than white people at the Super Bowl?
I'm betting it's cheetos.
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Deathclaw_Puncher
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### Re: Random thoughts...

Deathclaw_Puncher wrote:So, what foods and services will the alt-right boycott this year because they marketed to more than white people at the Super Bowl?
I'm betting it's cheetos.

That would cut out a large part of their diet. They might as well boycott Mountain Dew and tendies while they're at it.
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cmsellers
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### Re: Random thoughts...

Can someone give me a simple method of figuring out Pythagoras in your head? That's my random thought/request.
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Edgar Cabrera wrote:HOLY SHIT GUYS, IT'S DOGLOVINGJIM!!! HE'S HERE!!!

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### Re: Random thoughts...

DoglovingJim wrote:Can someone give me a simple method of figuring out Pythagoras in your head? That's my random thought/request.

If you mean doing the arithmetic to figure out the length of one of the sides from Pythagoras' theorem, not really. There's no real shortcut to a square root.

One thing that might help a bit is, if you're trying to solve:

$h = \sqrt{a^2 + b^2}$

if a and b happen to have a common factor x:

$\inline \dpi{150} \tiny h=\sqrt{(x\alpha)^2+(x\beta)^2}=\sqrt{x^2\alpha^2+x^2\beta^2}=\sqrt{x^2(\alpha^2+\beta^2)}=\sqrt{x^2}\sqrt{\alpha^2+\beta^2}=x\sqrt{\alpha^2+\beta^2}$

you can take that common factor outside the square root.
(N.B. equation assumes x > 0 which if you're talking about a triangle is probably the case. Properly speaking it should end up with |x| - that is, the modulus of x, or whichever of x and -x is not negative.)
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### Re: Random thoughts...

phpBB [video]

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Grimstone
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### Re: Random thoughts...

If you don't need a precise figure you can just memorize the perfect squares and ballpark it. Like, I don't know the square root of 20 off the top of my head but I know it's roughly halfway between four (square root of 16) and five (square root of 25).

If you do need a precise figure, pocket calculators are cheap.
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### Re: Random thoughts...

My boy's gonna play in the bigly, my boy's gonna give some head, my boy's gonna play in the bigly, my boy's gonna sleep in bed, aaaaahh ah in the biglys.
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### Re: Random thoughts...

What are the missing numbers in the following sequence?

2, 4, 6, 10, 16, 26, ?, ?

I can't for the life of me figure this out, can anyone explain it to me?
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Edgar Cabrera wrote:HOLY SHIT GUYS, IT'S DOGLOVINGJIM!!! HE'S HERE!!!

skoobadive wrote:It's the legendary DoglovingJim! Ohboy, this must be the greatest day of my life!

Cracked.com wrote:Initially, his interest in animals was "primarily a sexual attraction," but as he grew older, he also "developed the emotional attraction." We guess we could call what Jim does ... dog-lovin'

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### Re: Random thoughts...

2+4=6, 4+6=10, 6+10=16, 10+16=26, 16+26=42, 26+42=68
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"The struggle itself towards the heights is enough to fill a man's heart."

Grimstone
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### Re: Random thoughts...

Grimstone wrote:2+4=6, 4+6=10, 6+10=16, 10+16=26, 16+26=42, 26+42=68

You sir, are a genius, take that upvote because you earned it.
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Edgar Cabrera wrote:HOLY SHIT GUYS, IT'S DOGLOVINGJIM!!! HE'S HERE!!!

skoobadive wrote:It's the legendary DoglovingJim! Ohboy, this must be the greatest day of my life!

Cracked.com wrote:Initially, his interest in animals was "primarily a sexual attraction," but as he grew older, he also "developed the emotional attraction." We guess we could call what Jim does ... dog-lovin'

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### Re: Random thoughts...

Hmm, lets think of another random thought.

How would one go about figuring out the length for the hypotenuse in this?
random question.png (27.56 KiB) Viewed 2193 times

In my mind the formula should be to combine the opposite and the adjacent (using Tan) and find the square route of what they equal combined and that would be the length of x. But since I'm lacking the length of the adjacent I have no clue what to do, and in my head the multiple choice answers don't make sense.

I wonder what's the formula for when you only have the length of one side and an angle?

EDIT:
As for something random random I wonder what insects think about, do they ever wonder about us? What we are? Do they have ambitions?

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Edgar Cabrera wrote:HOLY SHIT GUYS, IT'S DOGLOVINGJIM!!! HE'S HERE!!!

skoobadive wrote:It's the legendary DoglovingJim! Ohboy, this must be the greatest day of my life!

Cracked.com wrote:Initially, his interest in animals was "primarily a sexual attraction," but as he grew older, he also "developed the emotional attraction." We guess we could call what Jim does ... dog-lovin'

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### Re: Random thoughts...

DoglovingJim wrote:How would one go about figuring out the length for the hypotenuse in this?
Spoiler: show

In my mind the formula should be to combine the opposite and the adjacent (using Tan) and find the square route of what they equal combined and that would be the length of x. But since I'm lacking the length of the adjacent I have no clue what to do, and in my head the multiple choice answers don't make sense.

I wonder what's the formula for when you only have the length of one side and an angle?

Forget Pythagoras here. Pythagoras links the three side lengths, and the length of one side is irrelevant to you.

You want basic trigonometry here: that links an angle and two side lengths. You generally need to know two of them and want to find a third. It doesn't matter which two: if you know two side lengths you can find an angle, and if you know a length and an angle you can find another length.

You have an angle (30°), one side length (Adjacent to that angle -5 units), and want another side length (hypotenuse - x).

There's three basic trig functions, tangent, cosine, and sine. Tan is not the one you want here, since Opposite (the base of the triangle - remember, we're working with the top angle, not θ) is neither known nor wanted.

SOH CAH TOA:
$sin{\theta} = \frac{Opp}{Hyp}; cos{\theta} = \frac{Adj}{Hyp}; tan{\theta} = \frac{Opp}{Adj};$

So with Adjacent and Hypotenuse, we want cosine.

$cos{30\degree}=\frac{5}{x}\Rightarrow x=\frac{5}{cos{30\degree}}=\frac{10}{\sqrt{3}}\approx5.8$

Of course, we can easily find the angle θ by subtracting the other two angles from 180°, so we could have used that, and sine, to find the hypotenuse. That would give us a very similar answer, because
sin(90°-θ) = cos(θ).

Also, not that anyone minds you asking in here I'm sure. It's not as though it can really be off-topic. But if you'd rather, we have a maths thread
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### Re: Random thoughts...

.
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### Re: Random thoughts...

DoglovingJim wrote:
What are the missing numbers in the following sequence?

2, 4, 6, 10, 16, 26, ?, ?

I can't for the life of me figure this out, can anyone explain it to me?

Fibonnaci?
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